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Distortion/OoO Working as Intended?

Exult Exult
in General Discussions

I thought of what I thought was going to be a cheeky aura reading build with OoO, Distortion, Kindred, and Guardian with a key and a black amber add-on. You could perhaps see what I was intending: some wall-hacks during loops, and free information with Distortion compensating for OoO revealing me. Interestingly, and maybe I'm just slow on things sometimes 'cause that's true, but I found that once OoO activates, and you have a Distortion token, it will consume the token but you won't be able to see the killer's aura.


Is this by design? I read both descriptions once over after that game and couldn't identify any contradictions in their requirements. Is this a bug? Just looking for some answers, because it doesn't seem like it should work that way.

Comments

  • IlliterateGenocide IlliterateGenocide

    Yes it's by design, Object ain't let you see the killers Aura in the normal sense.

    object shows YOUR aura to the killer so you would lose a token

    because object shows the killers Aura when they read YOURS

    So since they don't see ur aura because of Distortion you can't see theres

  • Exult Exult


    @IlliterateGenocide said:

    Yes it's by design, Object ain't let you see the killers Aura in the normal sense.

    object shows YOUR aura to the killer so you would lose a token

    because object shows the killers Aura when they read YOURS

    So since they don't see ur aura because of Distortion you can't see theres

    Oh I see. Thanks, I figured I was just being slow lol

  • Seraphor Seraphor

    It's a decent way of hiding the fact you have OoO, so that you can catch them off guard with it later in the game I suppose.

  • Exult Exult

    @Seraphor said:

    It's a decent way of hiding the fact you have OoO, so that you can catch them off guard with it later in the game I suppose.

    It almost works out like that, but realistically your Distortion gets stuck at one or zero tokens the entire game and you get little value out of it.

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